Doubling the Cube
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Origami(Paper Folding) Solution

1. Origami Solution by Hisashi Abe (ref.1)

Hisashi Abe published a very unique Delian solution in a Japanese mathematical magazine in 1980. The method is now described in ref.1, published in 2003.
He uses a traditional Japanese paper folding technique , called "Origami".

(1) Prepare a rectangular paper. All the corner angles must be exactly 90 degrees.
(2) Line AF, DG, BJ & HK are crease lines after folding along the lines.
(3) Distance between horizonral lines is 1 unit length.
(4) Distance between vertical lines is twice the unit value.
(5) With point H as a pivot, fold paper so that point A
falls on line HK and point B ,onto line DG.
Then distance ON is the cube root of 2.

You can see the process in animation.

For detail, go to the section Abe Hisashi's method.
********** Origami_Delian_desc.dwg *********

2. Origami Solution by Kazuo Haga (ref.2)

Ref.2 shows how to make a side length (15329/20000) by folding a square paper.

ABCD is a sqaure paper.
Step 1: move side CB so that C matches point E.Side CD cuts line AB at point f. Find point F to bisect Af.
Step 2: move corner C to point F. Folding line cuts CB at point g. Extend Bg by 50 %, to define point G.
Step 3: move corner D to point G. Foling line cuts CD at point H.
Length AH = 1.25993873 ,is a very good approximation of 21/3 = 1.259921...

You can see the process in animation.

For detail, go to the section Haga Kazuo's method.
********** Origami_Delian_2_desc.dwg *********

References

1. Abe, Hisashi: "Amazing Origami" , (in Japanese), 2003, ISBN 4-535-78409-4

2. Haga, Kazuo: "Origamics part - I" , (in Japanese), 1999, ISBN 4-535-78293-8


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Last Updated Nov 22, 2006

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